5ײ+11×+2=0 dengan rumus abc
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[tex]5 {x}^{2} + 11x + 2 = 0[/tex]
[tex] \frac{ - b \: \underline + \: \sqrt{ {b}^{2} - 4ac} }{2a} [/tex]
[tex]\frac{ - 11 \: \underline + \: \sqrt{ {11}^{2} - 4(5)(2)} }{2(5)} [/tex]
[tex]\frac{ - 11 \: \underline + \: \sqrt{ {121}^{} - 40} }{10} [/tex]
[tex]\frac{ - 11 \: \underline + \: \sqrt{ 81} }{10} [/tex]
[tex] \frac{ - 11 \:\underline + \: 9 }{10} [/tex]
[tex]\sf x_1 = \frac{ - 11 + 9}{10} [/tex]
[tex]\sf x_1 = \frac{ - 2}{10} [/tex]
[tex]\underline{\boxed{\sf\blue{x_1 = - \frac{1}{5} }}}[/tex]
[tex]\sf x_2 = \frac{ - 11 - 9}{10} [/tex]
[tex]\sf x_2 = - \frac{20}{10} [/tex]
[tex]\underline{\boxed{\sf\blue{x_2 = - 2 }}}[/tex]
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[tex]\bf Hp = \{\:-2\:,\:-\frac{1}{5}\:\}[/tex]
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